MATH SOLVE

3 months ago

Q:
# A business has $11,080 to spend on new laptops and tablet computers for its salespeople. The laptops cost $515 each. The tablets cost $285 each. The business wants each salesperson to have either a laptop or a tablet. There are 30 salespeople. How many of each type of computer should the business buy?

Accepted Solution

A:

With that information , we can develop 2 equations :

( where x = how many laptops you will buy and y = how many tablets you will buy )

x + y = 30

( There are 30 salespeople , so you only need to buy 30 eletronics )

515x + 285y = 11080

( Laptops cost 515 each and Tablets cost 285 each, you have to spend 11080)

Now that you have this system equations , you need to solve it.

To solve it you can use substitution or elimination.

( I will use substitution , but you can ask for elimination as well in the comments if you want )

Substitution:

x + y = 30

515x + 285y = 11080

In subtstitution , you need to isolate the value of a variable in one equation and apply it to the other equation.

In this case i will isolate x in the first equation and then apply it to the other equation:

x + y = 30

you can isolate the x by shifting y to the other side ( subtract y from both sides of the equation )

x + y - y = 30 - y

x = 30 - y

Now that we have the values of x , apply it to the other equation:

515x + 285y = 11080

515(30 - y ) + 285y = 11080

15450 - 515y + 285y = 11080

Combine like terms

-230y + 15450 = 11080

shift 15450 to the other side by subtracting both sides by 15450 :

-230y + 15450 - 15450 = 11080 - 15450

-230y = - 4370

To isolate y , divide both sides of the equation by - 230:

-230/-230y = -4370/-230

y = 19

Now that you have the value of y , apply it to one of the equations to get the x value :

x + y = 30

x + 19 =30

sutract 19 from both sides :

x = 11

Awnser : They have to buy 11 laptops and 19 tablets

I hope you understood my brief explanation. And please mark this awnser as Branliest if you think it deserves it . Thx :)

( where x = how many laptops you will buy and y = how many tablets you will buy )

x + y = 30

( There are 30 salespeople , so you only need to buy 30 eletronics )

515x + 285y = 11080

( Laptops cost 515 each and Tablets cost 285 each, you have to spend 11080)

Now that you have this system equations , you need to solve it.

To solve it you can use substitution or elimination.

( I will use substitution , but you can ask for elimination as well in the comments if you want )

Substitution:

x + y = 30

515x + 285y = 11080

In subtstitution , you need to isolate the value of a variable in one equation and apply it to the other equation.

In this case i will isolate x in the first equation and then apply it to the other equation:

x + y = 30

you can isolate the x by shifting y to the other side ( subtract y from both sides of the equation )

x + y - y = 30 - y

x = 30 - y

Now that we have the values of x , apply it to the other equation:

515x + 285y = 11080

515(30 - y ) + 285y = 11080

15450 - 515y + 285y = 11080

Combine like terms

-230y + 15450 = 11080

shift 15450 to the other side by subtracting both sides by 15450 :

-230y + 15450 - 15450 = 11080 - 15450

-230y = - 4370

To isolate y , divide both sides of the equation by - 230:

-230/-230y = -4370/-230

y = 19

Now that you have the value of y , apply it to one of the equations to get the x value :

x + y = 30

x + 19 =30

sutract 19 from both sides :

x = 11

Awnser : They have to buy 11 laptops and 19 tablets

I hope you understood my brief explanation. And please mark this awnser as Branliest if you think it deserves it . Thx :)