What is the absolute value of the complex number -4-sqrt2i
Accepted Solution
A:
Answer:=β18
Step-by-step explanation:The absolute value of a complex number is its distance from zero on graph. The formula for absolute value of a complex number is:
|a+bi|= β(a^2+b^2 )
where a is the real part of the complex number and b is the imaginary part of the complex number.
So for the given number,
a= -4
b=-β2
Putting in the formula:
|-4-β2 i|= β((-4)^2+(-β2)^2 )
= β(16+2)
=β18 Β ..